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Cantor's intersection theorem - Printable Version +- MKLab (https://mklab.gr) +-- Forum: [INDEX] (https://mklab.gr/forumdisplay.php?fid=1) +--- Forum: MATHEMATICS (https://mklab.gr/forumdisplay.php?fid=3) +---- Forum: ARTICLES (https://mklab.gr/forumdisplay.php?fid=13) +----- Forum: CALCULUS AND ANALYSIS (https://mklab.gr/forumdisplay.php?fid=149) +----- Thread: Cantor's intersection theorem (/showthread.php?tid=1587) |
Cantor's intersection theorem - mklabgr - 08-13-2026 Cantor's intersection theorem Summary Cantor’s Intersection Theorem is a fundamental result connecting nested sets, compactness, and completeness. In its topological form, it says that if we have a decreasing sequence of non-empty compact closed sets $$ C_0\supseteq C_1\supseteq C_2\supseteq\cdots, $$ then they must have at least one point in common: $$ \bigcap_{k=0}^{\infty}C_k\neq\varnothing. $$ For subsets of $\mathbb R$, compactness can be replaced by the more familiar conditions closed and bounded. Thus an infinite sequence of nested, non-empty, closed and bounded subsets cannot gradually “lose” every point. A simple example is $C_k=[0,1/k]$: although the intervals become arbitrarily small, their intersection remains ${0}$. The assumptions matter: $(0,1/k)$ has empty intersection because the intervals are not closed, while $[k,\infty)$ has empty intersection because the sets are unbounded. An especially important version occurs in a complete metric space. If the nested sets $C_k$ are non-empty and closed and their diameters satisfy $$ \lim_{k\to\infty}\operatorname{diam}(C_k)=0, $$ then their intersection contains exactly one point: $$ \bigcap_{k=1}^{\infty}C_k={x}. $$ The idea is to choose $x_k\in C_k$; because the sets become arbitrarily small, $(x_k)$ is a Cauchy sequence. Completeness guarantees that it converges, while closedness ensures that its limit belongs to every $C_k$. Remarkably, the converse also holds: this nested-set property characterizes completeness of metric spaces. The theorem also helps explain why the Cantor set is non-empty, since it is constructed as the intersection of a decreasing sequence of non-empty closed bounded sets. Key takeaways
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